At a constant temperature and pressure,the ra | vedclass

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(B) According to Graham's Law of Diffusion,the rate of diffusion $(r)$ of a gas is inversely proportional to the square root of its density $(d)$: $r

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$4 : 1$

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(B) According to Graham's Law of Diffusion,the rate of diffusion $(r)$ of a gas is inversely proportional to the square root of its density $(d)$: $r \propto \frac{1}{\sqrt{d}}$.Given the ratio of densities $\frac{d_1}{d_2} = \frac{1}{16}$.The ratio of their rates of diffusion is $\frac{r_1}{r_2} = \sqrt{\frac{d_2}{d_1}}$.Substituting the values: $\frac{r_1}{r_2} = \sqrt{\frac{16}{1}} = \frac{4}{1}$.Therefore,the ratio of their rates of diffusion is $4 : 1$.

At a constant temperature and pressure,the ratio of the densities of two gases is $1 : 16$. The ratio of their rates of diffusion will be ........

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