What is the angular momentum of an electron i | vedclass

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(D) The energy of an electron in the $n^{th}$ orbit of an $H$ atom is given by $E_n = -13.6 	imes \frac{Z^2}{n^2} \ eV$. For $H$ atom,$Z = 1$,so $E_n

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$2.1 	imes 10^{-34} \ J \cdot s$

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(D) The energy of an electron in the $n^{th}$ orbit of an $H$ atom is given by $E_n = -13.6 	imes \frac{Z^2}{n^2} \ eV$. For $H$ atom,$Z = 1$,so $E_n = -13.6 / n^2 \ eV$. Given $E_n = -3.4 \ eV$,we have $-3.4 = -13.6 / n^2$,which implies $n^2 = 4$,so $n = 2$. The angular momentum $L$ is given by Bohr's postulate: $L = \frac{nh}{2\pi}$. Substituting $n = 2$ and $h = 6.626 	imes 10^{-34} \ J \cdot s$: $L = \frac{2 	imes 6.626 	imes 10^{-34}}{2 	imes 3.14} \approx 2.1 	imes 10^{-34} \ J \cdot s$.

What is the angular momentum of an electron in the orbit of an $H$ atom where the energy of the electron is $-3.4 \ eV$?

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