If the velocity of an electron in the n^{th} | vedclass

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(A) The velocity of an electron in the $n^{th}$ orbit of a hydrogen atom is given by the formula: $v = 2.18 	imes 10^6 	imes \frac{Z}{n} \, m \, s^{

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$2$

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(A) The velocity of an electron in the $n^{th}$ orbit of a hydrogen atom is given by the formula: $v = 2.18 	imes 10^6 	imes \frac{Z}{n} \, m \, s^{-1}$.Given velocity $v = 0.0109 	imes 10^{10} \, cm \, s^{-1}$.Converting to $m \, s^{-1}$: $v = 0.0109 	imes 10^{10} 	imes 10^{-2} \, m \, s^{-1} = 1.09 	imes 10^6 \, m \, s^{-1}$.For a hydrogen atom,$Z = 1$.Substituting the values: $1.09 	imes 10^6 = 2.18 	imes 10^6 	imes \frac{1}{n}$.Therefore,$n = \frac{2.18 	imes 10^6}{1.09 	imes 10^6} = 2$.

If the velocity of an electron in the $n^{th}$ orbit of a hydrogen atom is $0.0109 \times 10^{10} \, cm \, s^{-1}$,what is the value of $n$?

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