How many H atoms are present in 0.46 , g of e | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The molar mass of ethanol $[C_2H_5OH]$ is $(2 	imes 12) + (6 	imes 1) + 16 = 46 \, g/mol$.Number of moles of ethanol $= \frac{	ext{Given mass}}

Vedclass · Accepted Answer

$3.6 	imes 10^{22}$

Vedclass · Answer

(A) The molar mass of ethanol $[C_2H_5OH]$ is $(2 	imes 12) + (6 	imes 1) + 16 = 46 \, g/mol$.Number of moles of ethanol $= \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{0.46 \, g}{46 \, g/mol} = 0.01 \, mol = 10^{-2} \, mol$.Each molecule of $C_2H_5OH$ contains $6$ hydrogen atoms.Therefore,the number of moles of $H$ atoms $= 6 	imes 10^{-2} \, mol$.Number of $H$ atoms $= 	ext{moles} 	imes N_A = 6 	imes 10^{-2} 	imes 6.022 	imes 10^{23} \approx 3.61 	imes 10^{22}$ atoms.Thus,the correct option is $A$.

How many $H$ atoms are present in $0.46 \, g$ of ethanol $[C_2H_5OH]$?

Similar Questions

The number of oxygen atoms in $0.2 \ mol$ of sodium carbonate decahydrate is :-

If $N_A$ is Avogadro’s number,then the number of valence electrons in $4.2 \ g$ of nitride ions $(N^{3 -})$ is ................... $N_A$.

The number of hydrogen atoms present in $5.4 \ g$ of urea is : (Given : Molar mass of urea: $60 \ g \ mol^{-1}$, $N_{A} = 6.022 \times 10^{23} \ particles \ mol^{-1}$)

If $3.01 \times 10^{20}$ molecules are removed from $98 \ mg$ of $H_2SO_4$,then the number of moles of $H_2SO_4$ left are:

Which one of the following statements is incorrect?

Vedclass Test Series

Exam Paper Generator

Online Exam Module