What is the hybridization of the Cl atom in C | vedclass

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(A) The hybridization of the central atom is calculated using the formula: $H = \frac{1}{2} (V + M - C + A)$,where $V$ is the number of valence electr

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$sp^3$

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(A) The hybridization of the central atom is calculated using the formula: $H = \frac{1}{2} (V + M - C + A)$,where $V$ is the number of valence electrons of the central atom,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.For $ClO^{-}_2$:$V = 7$ (for $Cl$),$M = 0$ (oxygen is divalent),$C = 0$,$A = 1$ (for $-1$ charge).$H = \frac{1}{2} (7 + 0 - 0 + 1) = \frac{8}{2} = 4$.$A$ value of $4$ corresponds to $sp^3$ hybridization.

What is the hybridization of the $Cl$ atom in $ClO^{-}_2$?

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