The angle between two hybrid orbitals is 105^ | vedclass

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Question

(C) The relationship between the bond angle $(	heta)$ and the $s-$character $(s)$ in hybrid orbitals is given by the formula: $\cos 	heta = \frac{s}

Vedclass · Accepted Answer

$22 - 23 \%$

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(C) The relationship between the bond angle $(	heta)$ and the $s-$character $(s)$ in hybrid orbitals is given by the formula: $\cos 	heta = \frac{s}{s-1}$.Given $	heta = 105^o$,we have $\cos(105^o) = -0.2588$.Substituting this into the equation: $-0.2588 = \frac{s}{s-1}$.$-0.2588(s-1) = s$.$-0.2588s + 0.2588 = s$.$1.2588s = 0.2588$.$s = \frac{0.2588}{1.2588} \approx 0.2056$.Converting to percentage,$s \approx 20.56 \%$.Among the given options,the value closest to this result is $22 - 23 \%$.

The angle between two hybrid orbitals is $105^o$. The $s-$character of the hybrid orbitals will be ..............

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