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(B) In the hydroxide $E-O-H$,the nature depends on the electronegativity difference between $E$ and $O$ and between $O$ and $H$. If the electronegativ

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(B) In the hydroxide $E-O-H$,the nature depends on the electronegativity difference between $E$ and $O$ and between $O$ and $H$. If the electronegativity difference between $E$ and $O$ is large (greater than $1.4$),the $E-O$ bond is highly polar and breaks to release $OH^-$ ions. Therefore,the compound acts as a base. Conversely,if the electronegativity difference between $O$ and $H$ is greater,the $O-H$ bond breaks to release $H^+$ ions,making the compound acidic.

If the difference in electronegativity between $E$ and $O$ is greater than $1.4$,determine the nature of the hydroxide $E-O-H$ of element $E$.

Similar Questions

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