Identify the product B in the following react | vedclass

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(D) $1$. The reaction of aniline $(C_6H_5NH_2)$ with $NaNO_2/HCl$ at $0^\circ-5^\circ C$ is a diazotization reaction,which produces benzenediazonium c

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$N,N$-Dimethyl$-4-$phenylazoaniline

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(D) $1$. The reaction of aniline $(C_6H_5NH_2)$ with $NaNO_2/HCl$ at $0^\circ-5^\circ C$ is a diazotization reaction,which produces benzenediazonium chloride $(A = C_6H_5N_2^+Cl^-)$.$2$. The subsequent reaction of benzenediazonium chloride with $N,N$-dimethylaniline $(Ph-N(CH_3)_2)$ is an electrophilic aromatic substitution reaction known as a coupling reaction.$3$. The diazonium ion acts as an electrophile and attacks the para-position of the $N,N$-dimethylaniline ring to form an azo dye.$4$. The product $B$ is $p$-(dimethylamino)azobenzene,which is also known as $N,N$-dimethyl$-4-$phenylazoaniline.

Identify the product $B$ in the following reaction:
$C_6H_5NH_2$ $\xrightarrow[0^\circ-5^\circ C]{NaNO_2/HCl} A$ $\xrightarrow{Ph-N(CH_3)_2} B$

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Identify the product $B$ in the following reaction:$C_6H_5NH_2$ $\xrightarrow[0^\circ-5^\circ C]{NaNO_2/HCl} A$ $\xrightarrow{Ph-N(CH_3)_2} B$