Product $(B)$ of this reaction is:

The correct sequence of reagents for the following transformation is:

The final product $A$, formed in the following multistep reaction sequence is:

The product $(A)$ is:

$E \xleftarrow{KOH/Br_2} D \xleftarrow{H_2O_2/OH^{-} \atop (Partial \ Hydrolysis)} C \xleftarrow{NaCN} C_2H_5-Cl$ $\xrightarrow{AgCN} A$ $\xrightarrow{LiAlH_4} B$
What is the relationship between $B$ and $E$?

You have been given four bottles marked $A, B, C$ and $D$ each containing one of the organic compounds given below:

$I: C_6H_5CH_2NH_2$	$II: C_6H_5CH_2COOH$
$III: C_6H_5CH_2CH_3$	$IV: C_6H_5CH_2CH(NH_2)COOH$

The following observations were made:
$(i)$ The compound in bottle $A$ did not dissolve in either $1 \ N \ NaOH$ or $1 \ N \ HCl$.
$(ii)$ The compound in bottle $B$ dissolved in $1 \ N \ NaOH$ but not in $1 \ N \ HCl$.
$(iii)$ The compound in bottle $C$ dissolved in both $1 \ N \ NaOH$ and $1 \ N \ HCl$.
$(iv)$ The compound in bottle $D$ did not dissolve in $1 \ N \ NaOH$ but dissolved in $1 \ N \ HCl$.
$(a)$ Indicate the compounds in: bottle $A = \dots$,bottle $B = \dots$,bottle $C = \dots$ and bottle $D = \dots$.
$(b)$ The compound with the highest solubility in distilled water is .......