The product $(A)$ is:

$A$ colourless substance $'A'$ $(C_6H_7N)$ is sparingly soluble in water and gives a water-soluble compound $'B'$ on treating with mineral acid. On reacting with $CHCl_3$ and alcoholic potash,$'A'$ produces an obnoxious smell due to the formation of compound $'C'$. Reaction of $'A'$ with benzenesulphonyl chloride gives compound $'D'$ which is soluble in alkali. With $NaNO_2$ and $HCl$,$'A'$ forms compound $'E'$ which reacts with phenol in an alkaline medium to give an orange dye $'F'$. Identify compounds $'A'$ to $'F'$.

What are $X$ and $Y$ respectively in the following set of reactions?

$Ph-NH_2$ $\xrightarrow{CH_3Cl \ (2 \ mole)} (A)$ $\xrightarrow{Ph-N_2^+ Cl^-} (B) \ (\text{major})$
Butter yellow is the product of the above reaction.

Which of the following compounds can form alcohol with $NaNO_2/HCl$?

Consider the following reaction sequence starting from $p$-nitrotoluene:
$(i)$ $\text{Sn/HCl; OH}^-$
(ii) $(\text{CH}_3\text{CO})_2\text{O}$
(iii) $\text{Br}_2/\text{AlBr}_3$
(iv) $\text{H}_3\text{O}^+$
When the final product $(P)$ is subjected to Carius analysis using $\text{AgNO}_3$, $1.0 \text{ g}$ of the product $(P)$ will produce . . . . . . $\text{g}$ of the precipitate of $\text{AgBr}$. (Nearest Integer)
(Given: molar mass in $\text{g mol}^{-1}$: $\text{C} = 12, \text{H} = 1, \text{O} = 16, \text{N} = 14, \text{Br} = 80, \text{Ag} = 108$)