Identify the final product Z in the following | vedclass

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(A) $1$. The reaction of aniline with acetyl chloride $(CH_3COCl)$ in the presence of a base (like pyridine) leads to the formation of acetanilide $(X

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$p$-Bromoaniline

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(A) $1$. The reaction of aniline with acetyl chloride $(CH_3COCl)$ in the presence of a base (like pyridine) leads to the formation of acetanilide $(X)$,which is $C_6H_5NHCOCH_3$.$2$. The acetanilide group $(-NHCOCH_3)$ is an ortho/para-directing group. Due to steric hindrance,the para-substitution is the major product when treated with $Br_2$ in the presence of a Lewis acid catalyst like $AlBr_3$ (or $FeBr_3$). Thus,$Y$ is $p$-bromoacetanilide.$3$. Finally,the hydrolysis of $p$-bromoacetanilide $(Y)$ with $H_3O^+$ removes the acetyl protecting group to regenerate the amino group,yielding $p$-bromoaniline $(Z)$ as the final product.

Identify the final product $Z$ in the following reaction sequence:
$Aniline$ $\xrightarrow{CH_3COCl} X$ $\xrightarrow{Br_2/AlBr_3} Y$ $\xrightarrow{H_3O^+} Z$

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Identify the final product $Z$ in the following reaction sequence:$Aniline$ $\xrightarrow{CH_3COCl} X$ $\xrightarrow{Br_2/AlBr_3} Y$ $\xrightarrow{H_3O^+} Z$