The rate constant of a reaction at 25,^oC is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: $T_1 = 25\,^oC = 298\,K$,$T_2 = 35\,^oC = 308\,K$. Rate constant $k_1 = 1 	imes 10^{-3}\,s^{-1}$. Since the rate doubles,$k_2 = 2 	imes k

Vedclass · Accepted Answer

$53$

Vedclass · Answer

(C) Given: $T_1 = 25\,^oC = 298\,K$,$T_2 = 35\,^oC = 308\,K$. Rate constant $k_1 = 1 	imes 10^{-3}\,s^{-1}$. Since the rate doubles,$k_2 = 2 	imes k_1 = 2 	imes 10^{-3}\,s^{-1}$. Using the Arrhenius equation: $\log(\frac{k_2}{k_1}) = \frac{E_a}{2.303R} 	imes (\frac{T_2 - T_1}{T_1 T_2})$. $\log(2) = \frac{E_a}{2.303 	imes 8.314} 	imes (\frac{308 - 298}{308 	imes 298})$. $0.3010 = \frac{E_a}{19.147} 	imes (\frac{10}{91784})$. $E_a = \frac{0.3010 	imes 19.147 	imes 91784}{10} \approx 52897\,J\,mol^{-1} \approx 53\,kJ\,mol^{-1}$.

The rate constant of a reaction at $25\,^oC$ is $1 \times 10^{-3}\,s^{-1}$. If the rate of the reaction doubles when the temperature is increased to $35\,^oC$,the activation energy of the reaction is .......... $kJ\, mol^{-1}$.

Similar Questions

What is the slope of the straight line for the graph drawn between $\ln k$ and $\frac{1}{T}$,where $k$ is the rate constant of a reaction at temperature $T$?

Which plot of $\ln k$ vs $\frac{1}{T}$ is consistent with the Arrhenius equation?

For an elementary chemical reaction, the Arrhenius plot is given below. If the energy of activation is $6.64 \ kJ \ mol^{-1}$ and $R = 8.3 \ J \ K^{-1} \ mol^{-1}$, the temperature at which the rate constant becomes $e^2 \ min^{-1}$, is (in $K$)

For a chemical reaction,the rate of reaction doubles when the temperature increases by $10\,^oC$. If the temperature is increased from $10\,^oC$ to $100\,^oC$,the rate of reaction will increase by a factor of .....

$A$ student determined the value of the rate constant,$k$,for a chemical reaction at several different temperatures. Which of the following graphs of the student's data would give a straight line?

Vedclass Test Series

Exam Paper Generator

Online Exam Module