Which of the following complexes does not exh | vedclass

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(A) $1$. In $[CoF_6]^{3-}$,the oxidation state of $Co$ is $+3$. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$. $F^-$ is a weak field ligand

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$[CoF_6]^{3-}$

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(A) $1$. In $[CoF_6]^{3-}$,the oxidation state of $Co$ is $+3$. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$. $F^-$ is a weak field ligand,so it does not cause pairing of electrons. Thus,it undergoes $sp^3d^2$ hybridization (outer orbital complex).$2$. In $[Co(NH_3)_6]^{3+}$,$Co^{3+}$ is $[Ar] 3d^6$. $NH_3$ is a strong field ligand,causing pairing of electrons in $3d$ orbitals,leading to $d^2sp^3$ hybridization.$3$. In $[Fe(CN)_6]^{3-}$,$Fe^{3+}$ is $[Ar] 3d^5$. $CN^-$ is a strong field ligand,causing pairing,leading to $d^2sp^3$ hybridization.$4$. In $[Cr(NH_3)_6]^{3+}$,$Cr^{3+}$ is $[Ar] 3d^3$. It utilizes two $3d$ orbitals,one $4s$ orbital,and three $4p$ orbitals to form $d^2sp^3$ hybridization.$5$. Therefore,$[CoF_6]^{3-}$ is the only complex that exhibits $sp^3d^2$ hybridization instead of $d^2sp^3$.

Coordination number and type of hybridisation	Distribution of hybrid orbitals in space
$a. 4, sp^3$	$i. \text{trigonal bipyramidal}$
$b. 4, dsp^2$	$ii. \text{octahedral}$
$c. 5, sp^3d$	$iii. \text{tetrahedral}$
$d. 6, d^2sp^3$	$iv. \text{square planar}$

Which of the following complexes does not exhibit $d^2sp^3$ hybridization?

Similar Questions

When $Ag^{+}$ reacts with excess of sodium thiosulphate,the obtained species having charge and geometry respectively will be?

The number of species from the following that are involved in $sp^3 d^2$ hybridization is $[Co(NH_3)_6]^{3+}, SF_6, [CrF_6]^{3-}, [CoF_6]^{3-}, [Mn(CN)_6]^{3-}$ and $[MnCl_6]^{3-}$.

Which $d-$orbital of metal in $[Fe(CO)_5]$ is involved in hybridisation?

Assertion : $[FeF_6]^{3-}$ is a low spin complex.
Reason : Low spin complexes have a lesser number of unpaired electrons.

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