Which of the following statements is incorrec | vedclass

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(A) $1$. For $[Ni(CO)_4]$: $Ni$ is in $0$ oxidation state $(3d^8 4s^2)$. $CO$ is a strong field ligand,causing pairing of electrons. The hybridization

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$[Ni(CO)_4]$ $-$ Tetrahedral,Paramagnetic

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(A) $1$. For $[Ni(CO)_4]$: $Ni$ is in $0$ oxidation state $(3d^8 4s^2)$. $CO$ is a strong field ligand,causing pairing of electrons. The hybridization is $sp^3$,resulting in a tetrahedral geometry and diamagnetic nature (all electrons paired).$2$. For $[Ni(CN)_4]^{2-}$: $Ni$ is in $+2$ oxidation state $(3d^8)$. $CN^-$ is a strong field ligand,causing pairing. The hybridization is $dsp^2$,resulting in a square planar geometry and diamagnetic nature.$3$. For $[NiCl_4]^{2-}$: $Ni$ is in $+2$ oxidation state $(3d^8)$. $Cl^-$ is a weak field ligand,no pairing occurs. The hybridization is $sp^3$,resulting in a tetrahedral geometry and paramagnetic nature (two unpaired electrons).$4$. Comparing these with the options,statement $A$ is incorrect because $[Ni(CO)_4]$ is diamagnetic,not paramagnetic.

Which of the following statements is incorrect?

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