For the reaction CH_2 = CH_2 + Br_2 xrightarr | vedclass

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Question

(D) The reaction of ethene with bromine in the presence of aqueous $NaI$ is an electrophilic addition reaction. $Br_2$ adds to the double bond to form

Vedclass · Accepted Answer

Only $CH_2I-CH_2I$ is formed.

Vedclass · Answer

(D) The reaction of ethene with bromine in the presence of aqueous $NaI$ is an electrophilic addition reaction. $Br_2$ adds to the double bond to form a cyclic bromonium ion intermediate. In the presence of $I^-$ ions (from $NaI$),the intermediate can be attacked by either $Br^-$ or $I^-$. Thus,the products formed are $CH_2Br-CH_2Br$ ($1$,$2$-dibromoethane) and $CH_2Br-CH_2I$ ($1$-bromo$-2-$iodoethane). Statement $D$ is incorrect because $CH_2I-CH_2I$ is not the primary product of this reaction.

For the reaction $CH_2 = CH_2 + Br_2 \xrightarrow{NaI_{(aq)}}$,which of the following statements is $NOT$ correct?

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