Ozonolysis of an alkene with molecular formul | vedclass

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(A) The ozonolysis of an alkene involves the cleavage of the $C=C$ double bond to form two carbonyl compounds. To find the original alkene,we join the

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$2, 2, 4-$ trimethyl $-3-$ hexene

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(A) The ozonolysis of an alkene involves the cleavage of the $C=C$ double bond to form two carbonyl compounds. To find the original alkene,we join the two carbonyl products by removing the oxygen atoms and forming a double bond between the carbon atoms of the carbonyl groups. The products are $2, 2-$ dimethylpropanal $(CH_3)_3C-CHO$ and $2-$ butanone $CH_3-CO-CH_2-CH_3$. Joining these: $(CH_3)_3C-CH=C(CH_3)-CH_2-CH_3$. Counting the carbons: $5$ (from the aldehyde part) $+ 4$ (from the ketone part) $= 9$ carbons. The structure is $2, 2, 4-$ trimethyl $-3-$ hexene. Thus,the correct option is $A$.

Ozonolysis of an alkene with molecular formula $C_9H_{18}$ yields $2, 2-$ dimethylpropanal and $2-$ butanone. The alkene is ....................

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