Ethylene reacts with Br_2 to give 1, 2-dibrom | vedclass

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(B) The reaction of ethylene with $Br_2$ proceeds via the formation of a cyclic bromonium ion intermediate. When $Br_2$ approaches the double bond of

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Cyclic bromonium ion

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(B) The reaction of ethylene with $Br_2$ proceeds via the formation of a cyclic bromonium ion intermediate. When $Br_2$ approaches the double bond of ethylene,the electron-rich double bond attacks one of the bromine atoms,displacing the other as a bromide ion $(Br^-)$. This results in the formation of a three-membered cyclic bromonium ion. The subsequent nucleophilic attack by the bromide ion $(Br^-)$ occurs from the side opposite to the cyclic bromonium ion,which leads to anti-addition.

Ethylene reacts with $Br_2$ to give $1, 2$-dibromoethane. Which intermediate is formed that leads to anti-addition?

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