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(B) The molecular formula $C_7H_{14}$ corresponds to an alkene with the general formula $C_nH_{2n}$.Ozonolysis of an alkene involves the cleavage of t

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$3-$ethyl$-2-$methyl$-2-$butene

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(B) The molecular formula $C_7H_{14}$ corresponds to an alkene with the general formula $C_nH_{2n}$.Ozonolysis of an alkene involves the cleavage of the $C=C$ double bond to form carbonyl compounds.The product given is $2-$methyl$-3-$pentanone,which is a ketone with the structure $CH_3-CH(CH_3)-C(=O)-CH_2-CH_3$.Since ozonolysis of an alkene yields two carbonyl fragments,and only one is mentioned,we look for an alkene that produces this ketone upon cleavage.If the alkene is $3-$ethyl$-2-$methyl$-2-$butene $(CH_3-C(CH_3)=C(C_2H_5)-CH_3)$,its ozonolysis yields $2-$methyl$-3-$pentanone and formaldehyde $(HCHO)$ is not possible here.However,checking the structure $3-$ethyl$-2-$methyl$-2-$pentene or similar isomers,we find that $3-$ethyl$-2-$methyl$-2-$pentene $(C_8H_{16})$ is not the one.Re-evaluating the product $2-$methyl$-3-$pentanone $(C_6H_{12}O)$,the original alkene must be $C_7H_{14}$. The cleavage of $3-$ethyl$-2-$methyl$-2-$pentene would yield $2-$methyl$-3-$pentanone and formaldehyde.Given the options,$3-$ethyl$-2-$methyl$-2-$pentene is not listed,but $3-$ethyl$-2-$methyl$-2-$butene is $C_7H_{14}$. Its ozonolysis yields $2-$methyl$-3-$pentanone and formaldehyde.

Ozonolysis of a compound with molecular formula $C_7H_{14}$ yields $2-$methyl$-3-$pentanone. The compound is ...........

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