The ozonolysis (O_3, H_2O) of (CH_3)_2CH-C eq | vedclass

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Question

(A) Ozonolysis of an alkyne with $O_3$ followed by hydrolysis $(H_2O)$ results in the cleavage of the triple bond to form diketones or carboxylic acid

Vedclass · Accepted Answer

$(CH_3)_2CHCOOH + CH_3COOH$

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(A) Ozonolysis of an alkyne with $O_3$ followed by hydrolysis $(H_2O)$ results in the cleavage of the triple bond to form diketones or carboxylic acids depending on the conditions. For internal alkynes,the triple bond is cleaved to form two carboxylic acids.The reaction is: $(CH_3)_2CH-C \equiv C-CH_3 + O_3 / H_2O \rightarrow (CH_3)_2CHCOOH + CH_3COOH$.Thus,the products are isobutyric acid and acetic acid.

The ozonolysis $(O_3, H_2O)$ of $(CH_3)_2CH-C \equiv C-CH_3$ gives:

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