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(D) For a compound to exhibit optical isomerism,it must contain at least one chiral carbon atom (a carbon atom bonded to four different groups).$1, 1-

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$1, 2-$ Dichloropropane

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(D) For a compound to exhibit optical isomerism,it must contain at least one chiral carbon atom (a carbon atom bonded to four different groups).$1, 1-$ Dichloropropane: $CH_3-CH_2-CHCl_2$ (No chiral carbon)$2, 2-$ Dichloropropane: $CH_3-CCl_2-CH_3$ (No chiral carbon)$1, 3-$ Dibromopropane: $Br-CH_2-CH_2-CH_2-Br$ (No chiral carbon)$1, 2-$ Dichloropropane: $CH_3-CHCl-CH_2Cl$. Here,the $C-2$ atom is bonded to a methyl group $(-CH_3)$,a hydrogen atom $(-H)$,a chlorine atom $(-Cl)$,and a chloromethyl group $(-CH_2Cl)$. Since all four groups are different,$C-2$ is a chiral center.Therefore,$1, 2-$ Dichloropropane exhibits optical isomerism.

Which of the following compounds will exhibit optical isomerism?

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