Which of the following compounds will undergo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The rate of $S_{N^1}$ reaction depends on the stability of the carbocation intermediate formed during the rate-determining step.More stable carboc

Vedclass · Accepted Answer

$CH_3CH_2CH_2CH(Cl)CH_2CH_3$

Vedclass · Answer

(B) The rate of $S_{N^1}$ reaction depends on the stability of the carbocation intermediate formed during the rate-determining step.More stable carbocations are formed more easily,leading to a faster $S_{N^1}$ reaction.The order of stability of carbocations is: $3^{\circ} > 2^{\circ} > 1^{\circ} > 	ext{methyl}$.Option $A$ $(C_6H_5Cl)$ is an aryl halide,which is very unreactive towards $S_{N^1}$ due to partial double bond character.Option $B$ is a $2^{\circ}$ alkyl halide $(CH_3CH_2CH_2CH(Cl)CH_2CH_3)$,which forms a $2^{\circ}$ carbocation.Options $C$ and $D$ are $1^{\circ}$ alkyl halides,which form less stable $1^{\circ}$ carbocations.Therefore,the $2^{\circ}$ alkyl halide in option $B$ will undergo $S_{N^1}$ reaction most easily among the given choices.

Which of the following compounds will undergo $S_{N^1}$ reaction most easily?

Similar Questions

What is the product obtained when $CCl_4$ is boiled with $KOH$?

An incorrect statement with respect to $S_N1$ and $S_N2$ mechanisms for alkyl halide is

The reaction $CH_3-CH(C_6H_5)-CH(Br)-C_6H_5 \xrightarrow{alc.KOH} A$. Identify the product $A$.

Chloropicrin is a strong lachrymatory compound and is used in war. It is prepared by

Which best describes the product of the following reaction?
$Ph-C(CH_3)(Br)-CD_3 \xrightarrow{K^+ t-BuO^-, E_2} \text{product}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module