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(D) The reaction is an $E_2$ elimination reaction.The substrate is a chiral alkyl bromide: $1-bromo-1-phenylethyl-d_3$ (where $d_3$ is $CD_3$).Upon tr

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Loss of chirality has occurred (the product is achiral)

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(D) The reaction is an $E_2$ elimination reaction.The substrate is a chiral alkyl bromide: $1-bromo-1-phenylethyl-d_3$ (where $d_3$ is $CD_3$).Upon treatment with a strong base like potassium tert-butoxide $(K^+ t-BuO^-)$,the reaction proceeds via an $E_2$ mechanism to form an alkene.The product formed is $Ph-C(=CH_2)-CD_3$ (or $Ph-C(CD_3)=CH_2$).This product is a planar alkene,which does not possess a chiral center.Therefore,the loss of chirality has occurred,and the product is achiral.

Which best describes the product of the following reaction?
$Ph-C(CH_3)(Br)-CD_3 \xrightarrow{K^+ t-BuO^-, E_2} \text{product}$

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Which best describes the product of the following reaction?$Ph-C(CH_3)(Br)-CD_3 \xrightarrow{K^+ t-BuO^-, E_2} \text{product}$