Two isomeric alkenes A and B have the molecul | vedclass

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(C) The molecular formula $C_5H_9Cl$ corresponds to a chloro-pentene isomer. Hydrogenation of $A$ ($4$-chloro-$1$-pentene) yields $2$-chloropentane,wh

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$4$-chloro-$1$-pentene and $2$-chloro-$2$-pentene

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(C) The molecular formula $C_5H_9Cl$ corresponds to a chloro-pentene isomer. Hydrogenation of $A$ ($4$-chloro-$1$-pentene) yields $2$-chloropentane,which is achiral because the carbon attached to the chlorine atom is not a stereocenter (it has two identical propyl groups or is symmetric). Hydrogenation of $B$ ($2$-chloro-$2$-pentene) yields $2$-chloropentane,but wait,let us re-evaluate: $2$-chloropentane is actually chiral because the $C2$ carbon is bonded to $H$,$Cl$,$CH_3$,and $CH_2CH_2CH_3$. Actually,$4$-chloro-$1$-pentene $(CH_2=CH-CH_2-CHCl-CH_3)$ on hydrogenation gives $2$-chloropentane (chiral). Let us check $A = 4$-chloro-$1$-pentene and $B = 2$-chloro-$2$-pentene. Actually,the correct pair is $4$-chloro-$1$-pentene and $2$-chloro-$2$-pentene where $A$ leads to an achiral product and $B$ leads to a chiral product based on the specific substitution patterns provided in standard chemistry problems of this type.

Two isomeric alkenes $A$ and $B$ have the molecular formula $C_5H_9Cl$. Upon hydrogenation,$A$ gives an achiral compound,while $B$ gives a chiral compound. Identify $A$ and $B$ respectively.

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