An alkene $A$ on reaction with $O_{3}$ and $Zn-H_{2}O$ gives propanone and ethanal in equimolar ratio. Addition of $HCl$ to alkene $A$ gives $B$ as the major product. The structure of product $B$ is:

$Ph-CH=CH_2 \xrightarrow[HBr]{(PhCOO)_2} \text{Product}$
Consider the above reaction:
$A$. The reaction proceeds through a more stable radical intermediate.
$B$. The role of peroxide is to generate $\dot{H}$ (Hydrogen radical).
$C$. During this reaction, benzene is formed as a byproduct.
$D$. $1-\text{Bromo}-2-\text{phenylethane}$ is formed as the minor product.
$E$. The same reaction in the absence of peroxide proceeds via a carbocation intermediate.
Identify the correct statements. Choose the correct answer from the options given below:

In the presence of peroxide,hydrogen chloride or hydrogen iodide do not give anti-Markovnikov addition to alkenes because...

At $530 \ K$,glycerol reacts with oxalic acid to produce:

$CH_2 = CH_2 \xrightarrow[KOH/H_2O]{KMnO_4} X = ......$

Which one of the following organic compounds decolourizes an alkaline $KMnO_4$ solution?