Identify the product of the following reactio | vedclass

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(A) The starting material is $1$-bromo-$3$-chlorobenzene.$1$. Treatment with $n$-butyllithium $(n-BuLi)$ leads to a halogen-metal exchange reaction. S

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$3-$chlorobenzoic acid

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(A) The starting material is $1$-bromo-$3$-chlorobenzene.$1$. Treatment with $n$-butyllithium $(n-BuLi)$ leads to a halogen-metal exchange reaction. Since bromine is more electropositive and forms a more stable organolithium intermediate than chlorine,the lithium atom selectively replaces the bromine atom,forming $3$-chlorophenyllithium.$2$. The resulting $3$-chlorophenyllithium reacts with carbon dioxide $(CO_2)$ to form a lithium carboxylate intermediate.$3$. Subsequent acidic workup $(H^+, H_2O)$ protonates the carboxylate to yield $3$-chlorobenzoic acid as the final product.

List-$I$ (Reaction)	List-$II$ (Name of reaction)
$A$. $2C_6H_5X + 2Na \xrightarrow{\text{Dry Ether}} C_6H_5-C_6H_5 + 2NaX$	$I$. Lucas reaction
$B$. $ArN_2^{+} X^{-} \xrightarrow[HCl]{Cu} ArCl + N_2 \uparrow + CuX$	$II$. Finkelstein reaction
$C$. $C_2H_5Br + NaI \xrightarrow{\text{Acetone}} C_2H_5I + NaBr$	$III$. Fittig reaction
$D$. $(CH_3)_3COH \xrightarrow[ZnCl_2]{HCl} (CH_3)_3CCl + H_2O$	$IV$. Gatterman reaction

List-$I$ (Reaction)	List-$II$ (Major product)
$A. \ CH_3CH=CH_2 \xrightarrow{HI}$	$I. \ 1\text{-bromo-}2\text{-phenylethane}$
$B. \ C_6H_5CH_2CH_3 \xrightarrow{Br_2/\Delta}$	$II. \ 1\text{-iodopropane}$
$C. \ C_6H_5CH=CH_2 \xrightarrow{HBr}$	$III. \ 2\text{-iodopropane}$
	$IV. \ 1\text{-bromo-}1\text{-phenylethane}$

Identify the product of the following reaction:

Similar Questions

The product $(B)$ of the above reaction is:

The products obtained in the above reactions $(1)$,$(2)$,and $(3)$ are:

The possible products formed in the following reaction are:

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