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Question

(A) The interplanar distance $d_{hkl}$ for a cubic system is given by the formula: $d_{hkl} = \frac{a}{\sqrt{h^2 + k^2 + l^2}}$.Given: $a = 450 \, pm$

Vedclass · Accepted Answer

$159$

Vedclass · Answer

(A) The interplanar distance $d_{hkl}$ for a cubic system is given by the formula: $d_{hkl} = \frac{a}{\sqrt{h^2 + k^2 + l^2}}$.Given: $a = 450 \, pm$, $h = 2$, $k = 2$, $l = 0$.Substituting the values: $d_{220} = \frac{450}{\sqrt{2^2 + 2^2 + 0^2}}$.$d_{220} = \frac{450}{\sqrt{4 + 4 + 0}} = \frac{450}{\sqrt{8}}$.$d_{220} = \frac{450}{2\sqrt{2}} = \frac{225}{\sqrt{2}}$.Using $\sqrt{2} \approx 1.414$, $d_{220} = \frac{225}{1.414} \approx 159.12 \, pm$.Thus, the distance is approximately $159 \, pm$.

Calculate the distance between two parallel $(220)$ planes in a crystal with an edge length of $450 \, pm$. (in $pm$)

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