Benzene and toluene form an ideal solution. I | vedclass

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(D) According to Raoult's Law,the partial vapor pressure of a component in an ideal solution is given by $p_i = x_i p_i^0$,where $x_i$ is the mole fra

Vedclass · Accepted Answer

Cannot be determined

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(D) According to Raoult's Law,the partial vapor pressure of a component in an ideal solution is given by $p_i = x_i p_i^0$,where $x_i$ is the mole fraction and $p_i^0$ is the vapor pressure of the pure component.However,the question provides the partial vapor pressures ($p_B = 1.55 \ kPa$ and $p_T = 1.85 \ kPa$) directly.In an ideal solution,the ratio of partial pressures is equal to the ratio of the products of mole fractions and pure vapor pressures.Since $p_B = x_B p_B^0$ and $p_T = x_T p_T^0$,the ratio of partial pressures is $\frac{p_B}{p_T} = \frac{x_B p_B^0}{x_T p_T^0}$.Without the pure vapor pressures ($p_B^0$ and $p_T^0$),the mole ratio $\frac{x_B}{x_T}$ cannot be calculated from the partial pressures alone.Therefore,the correct answer is that it cannot be determined.

Benzene and toluene form an ideal solution. If the partial vapor pressures of benzene and toluene are $1.55 \ kPa$ and $1.85 \ kPa$ respectively,what is the mole ratio of benzene to toluene in the solution?

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