2.0 , m , CH_3COOH undergoes 100 % dimerizati | vedclass

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(C) For $CH_3COOH$ in benzene,it undergoes dimerization: $2CH_3COOH \rightleftharpoons (CH_3COOH)_2$. The van't Hoff factor $i = 1 + (\frac{1}{n} - 1)

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$0.5 \, m$ solution of $NaNO_3$ with $100 \%$ ionization

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(C) For $CH_3COOH$ in benzene,it undergoes dimerization: $2CH_3COOH ightleftharpoons (CH_3COOH)_2$. The van't Hoff factor $i = 1 + (\frac{1}{n} - 1)\alpha$. Since $n = 2$ and $\alpha = 1$ ($100 \%$ dimerization),$i = 1 + (\frac{1}{2} - 1)(1) = 0.5$. The effective molality (osmotic pressure is proportional to $i 	imes m$) is $0.5 	imes 2.0 \, m = 1.0 \, m$. For isotonic solutions,the effective molality must be equal. Option $A$: $KNO_3 ightarrow K^+ + NO_3^-$,$i = 2$. Effective molality $= 2 	imes 1.0 \, m = 2.0 \, m$. Option $B$: $Ca(NO_3)_2 ightarrow Ca^{2+} + 2NO_3^-$,$i = 3$. Effective molality $= 3 	imes 1.0 \, m = 3.0 \, m$. Option $C$: $NaNO_3 ightarrow Na^+ + NO_3^-$,$i = 2$. Effective molality $= 2 	imes 0.5 \, m = 1.0 \, m$. Since the effective molality of $0.5 \, m \, NaNO_3$ is $1.0 \, m$,it is isotonic with the given solution.

$2.0 \, m \, CH_3COOH$ undergoes $100 \%$ dimerization in benzene. It will be isotonic with which of the following?

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