In a solution with molality m,if the solute e | vedclass

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(D) The elevation in boiling point is given by $\Delta T_b = i 	imes K_b 	imes m$. For a solute that dimerizes,the van't Hoff factor $i$ is given by

Vedclass · Accepted Answer

$mK_b / 3$

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(D) The elevation in boiling point is given by $\Delta T_b = i 	imes K_b 	imes m$. For a solute that dimerizes,the van't Hoff factor $i$ is given by $i = 1 - \alpha + \alpha / 2 = 1 - \alpha / 2$,where $\alpha$ is the degree of association. Since $0 \le \alpha \le 1$,the range for $i$ is $1 - 1/2 \le i \le 1 - 0$,which means $0.5 \le i \le 1$. Therefore,the range for $\Delta T_b$ is $0.5 mK_b \le \Delta T_b \le 1 mK_b$. Checking the options: $A) 0.5 mK_b$ (Possible at $\alpha = 1$) $B) 0.6 mK_b$ (Possible at $\alpha = 0.8$) $C) 0.75 mK_b$ (Possible at $\alpha = 0.5$) $D) 0.33 mK_b$ (Not possible as $i < 0.5$ is required,which is outside the range).

In a solution with molality $m$,if the solute exists in the form of a dimer,which of the following cannot be the elevation in the boiling point of the solution?

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