In the equilibrium N_{2(g)} + 3H_{2(g)} right | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Le Chatelier's principle: $1$. For the reaction $N_{2(g)} + 3H_{2(g)} \rightleftharpoons 2NH_{3(g)} + 22 \ kcal$,the forward reaction

Vedclass · Accepted Answer

Increase in pressure

Vedclass · Answer

(A) According to Le Chatelier's principle: $1$. For the reaction $N_{2(g)} + 3H_{2(g)} \rightleftharpoons 2NH_{3(g)} + 22 \ kcal$,the forward reaction is exothermic. Therefore,a decrease in temperature would favor the forward reaction. $2$. The number of moles of gaseous products is $2$,while the number of moles of gaseous reactants is $1 + 3 = 4$. $3$. According to Le Chatelier's principle,an increase in pressure shifts the equilibrium towards the side with fewer moles of gas. $4$. Thus,an increase in pressure favors the formation of $NH_3$.

In the equilibrium $N_{2(g)} + 3H_{2(g)} \rightleftharpoons 2NH_{3(g)} + 22 \ kcal$,the formation of ammonia is favored by:

Similar Questions

According to Le Chatelier's principle,if a gaseous mixture is compressed,what will be the effect on the equilibrium of the following reaction: $N_2O_{4(g)} \rightleftharpoons 2NO_{2(g)}$?

In a reversible reaction,a catalyst...

Le Chatelier's principle is applicable to which of the following?

The oxidation of $SO_2$ to $SO_3$ by $O_2$ is an exothermic reaction: $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g) + \text{Heat}$. The yield of $SO_3$ will increase if:

In which of the following equilibrium reactions,the equilibrium would shift to the right,if total pressure is increased?

Vedclass Test Series

Exam Paper Generator

Online Exam Module