How much heat will be evolved when 500 , mL o | vedclass

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(B) The number of equivalents of $H_2SO_4 = N 	imes V(L) = 0.2 	imes 0.5 = 0.1 \, eq$. Since $H_2SO_4$ is a diprotic acid,the number of moles of $H^

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$2.865 \, kJ$

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(B) The number of equivalents of $H_2SO_4 = N 	imes V(L) = 0.2 	imes 0.5 = 0.1 \, eq$. Since $H_2SO_4$ is a diprotic acid,the number of moles of $H^+$ ions $= 0.1 \, mol$. The number of equivalents of $KOH = N 	imes V(L) = 1 	imes 0.05 = 0.05 \, eq$. Since $KOH$ is a monoprotic base,the number of moles of $OH^-$ ions $= 0.05 \, mol$. The neutralization reaction is $H^+ + OH^- ightarrow H_2O$,where the enthalpy of neutralization is $-57.3 \, kJ/mol$. Since $OH^-$ is the limiting reagent $(0.05 \, mol Heat evolved $= 0.05 \, mol 	imes 57.3 \, kJ/mol = 2.865 \, kJ$.

How much heat will be evolved when $500 \, mL$ of $0.2 \, N \, H_2SO_4$ is mixed with $50 \, mL$ of $1 \, N \, KOH$?

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