The reactivity of borazole is higher than that of benzene because ...

Aluminium reacts with $NaOH$ and forms compound '$X$'. If the coordination number of aluminium in '$X$' is $6$, the correct formula of $X$ is:

Addition of mineral acid to an aqueous solution of Borax,the following compound is formed:

The composition of borax is:

$A$ compound $X$,of boron reacts with $NH_3$ on heating to give another compound $Y$,which is called inorganic benzene. The compound $X$ can be prepared by treating $BF_3$ with lithium aluminium hydride. The compounds $X$ and $Y$ are represented by the formulas.

The incorrect statement regarding $X$ in the given reaction is:
$BF_3 + LiAlH_4 \xrightarrow{\text{Ether}} X + LiF + AlF_3$