What is the hybridization of the central atom | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The hybridization of the central atom can be calculated using the formula: $H = \frac{1}{2} (V + M - C + A)$,where $V$ is the number of valence el

Vedclass · Accepted Answer

$sp^3$

Vedclass · Answer

(B) The hybridization of the central atom can be calculated using the formula: $H = \frac{1}{2} (V + M - C + A)$,where $V$ is the number of valence electrons of the central atom,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.For $NH_4^+$,the central atom is $N$ $(V = 5)$,$M = 4$ (four $H$ atoms),$C = 1$,and $A = 0$.$H = \frac{1}{2} (5 + 4 - 1 + 0) = \frac{8}{2} = 4$.$A$ value of $4$ corresponds to $sp^3$ hybridization.

What is the hybridization of the central atom in $NH_4^+$?

Similar Questions

The shape of the ethylene molecule is:

What type of hybridization is present in the $PCl_{5}$ molecule?

Explain the shape of $sp$,$sp^2$,and $sp^3$ hybrid orbitals.

Which type of overlap is involved in the formation of $O-H$ bonds in a water molecule?

What is the expected hybridization of $N$ in the given molecule?

Vedclass Test Series

Exam Paper Generator

Online Exam Module