The reaction of $HNO_3$ with $P_4O_{10}$ produces ....

  • A
    $N_2O_5$
  • B
    $NO_2$
  • C
    $N_2O_4$
  • D
    $N_2O$

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Statement $(A)$: Among the oxides of nitrogen, $NO$ and $NO_2$ are paramagnetic.
Statement $(B)$: $NO$ is paramagnetic in the gaseous state and diamagnetic in the liquid state.
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$(I)$ The principal reducing product is $NO$ gas.
$(II)$ $Cu$ metal is oxidised to $Cu^{2+}$ (aq.) ion which is blue in colour.
$(III)$ $NO$ is paramagnetic and has one unpaired electron in antibonding molecular orbital.
$(IV)$ $NO$ reacts with $O_2$ to produce $NO_2$ which is linear in shape.
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