Although CN^- and N_2 are isoelectronic,N_2 i | vedclass

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(A) $N_2$ and $CN^-$ are isoelectronic,both having $14$ electrons. $N_2$ is a neutral molecule with a very strong triple bond $(N \equiv N)$ and high

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Higher bond energy

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(A) $N_2$ and $CN^-$ are isoelectronic,both having $14$ electrons. $N_2$ is a neutral molecule with a very strong triple bond $(N \equiv N)$ and high bond dissociation energy $(941 \ kJ \ mol^{-1})$,making it chemically inert. $CN^-$ is an anion with a negative charge,which makes it more reactive as a nucleophile compared to the neutral $N_2$ molecule. Therefore,the inertness of $N_2$ compared to $CN^-$ is primarily due to its higher bond energy and stability as a neutral species.

Although $CN^-$ and $N_2$ are isoelectronic,$N_2$ is inert compared to $CN^-$,which is due to $........$.

Similar Questions

What is the effect of the following processes on the bond order in $N_{2}$ and $O_{2}$?
$(A)$ $N_{2} \to N_{2}^{+} + e^{-}$
$(B)$ $O_{2} \to O_{2}^{+} + e^{-}$

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