In which of the following ionisation processe | vedclass

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(C) The bond order is calculated as $\frac{N_b - N_a}{2}$,where $N_b$ is the number of bonding electrons and $N_a$ is the number of antibonding electr

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$NO \longrightarrow NO^{+}$

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(C) The bond order is calculated as $\frac{N_b - N_a}{2}$,where $N_b$ is the number of bonding electrons and $N_a$ is the number of antibonding electrons.$1$. For $O_2 \longrightarrow O_2^{+}$: $O_2$ (Paramagnetic,$BO = 2.0$) $\longrightarrow O_2^{+}$ (Paramagnetic,$BO = 2.5$).$2$. For $C_2 \longrightarrow C_2^{+}$: $C_2$ (Diamagnetic,$BO = 2.0$) $\longrightarrow C_2^{+}$ (Paramagnetic,$BO = 1.5$).$3$. For $NO \longrightarrow NO^{+}$: $NO$ (Paramagnetic,$BO = 2.5$) $\longrightarrow NO^{+}$ (Diamagnetic,$BO = 3.0$). Here,the bond order increases and the magnetic behavior changes from paramagnetic to diamagnetic.$4$. For $N_2 \longrightarrow N_2^{+}$: $N_2$ (Diamagnetic,$BO = 3.0$) $\longrightarrow N_2^{+}$ (Paramagnetic,$BO = 2.5$).

In which of the following ionisation processes does the bond energy increase and the magnetic behaviour change from paramagnetic to diamagnetic?

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