What is the product formed when phenol reacts with $Br_2$ in $CCl_4$ at low temperature?

In the following reaction, condition '$A$' is -

What is the product formed in the following reaction?
$C_6H_5OH + CCl_4 \xrightarrow[(2) \ H^{+}]{(1) \ NaOH}$

When phenol is treated with $D_{2}SO_{4} / D_{2}O$, some of the hydrogens get exchanged. The final product in this exchange reaction is

The major product of the following reaction is
$2-(2-hydroxyethyl)phenol$ $\xrightarrow[2. \, CH_3I \, (1. \, eq.)]{1. \, K_2CO_3}$

What amount of bromine will be required to convert $2 \ g$ of phenol into $2, 4, 6-$tribromophenol (in $g$)? $($Given molar mass in $g \ mol^{-1}$ of $C, H, O, Br$ are $12, 1, 16, 80$ respectively$)$