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(B) The reaction of phenol with carbon tetrachloride $(CCl_4)$ in the presence of aqueous sodium hydroxide $(NaOH)$ is known as the Reimer-Tiemann rea

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$o-$hydroxybenzoic acid

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(B) The reaction of phenol with carbon tetrachloride $(CCl_4)$ in the presence of aqueous sodium hydroxide $(NaOH)$ is known as the Reimer-Tiemann reaction (using $CCl_4$ variant).This reaction introduces a carboxylic acid group $( -COOH )$ at the ortho position of the phenol ring.Initially,the phenoxide ion reacts with the dichlorocarbene intermediate (generated from $CCl_4$ and $NaOH$) to form an ortho-substituted intermediate,which upon hydrolysis and acidification $(H^+)$ yields $o-$hydroxybenzoic acid (also known as salicylic acid).Therefore,the correct product is $o-$hydroxybenzoic acid.

What is the product formed in the following reaction?
$C_6H_5OH + CCl_4 \xrightarrow[(2) \ H^{+}]{(1) \ NaOH}$

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What is the product formed in the following reaction?$C_6H_5OH + CCl_4 \xrightarrow[(2) \ H^{+}]{(1) \ NaOH}$