(A) Let the oxidation state of $P$ be $x$. The oxidation states of $K$,$H$,and $O$ are $+1$,$+1$,and $-2$ respectively. The sum of oxidation states in

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(A) Let the oxidation state of $P$ be $x$. The oxidation states of $K$,$H$,and $O$ are $+1$,$+1$,and $-2$ respectively. The sum of oxidation states in a neutral molecule is $0$. $(+1) + 2(+1) + x + 2(-2) = 0$ $1 + 2 + x - 4 = 0$ $x - 1 = 0$ $x = +1$ Therefore,the oxidation state of $P$ in $KH_2PO_2$ is $+1$.