What is the oxidation state of carbon in CaC_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For $CaC_2$: The oxidation state of $Ca$ is $+2$. Let the oxidation state of $C$ be $x$. Thus,$+2 + 2x = 0$,which gives $x = -1$.For $K_2C_2O_4$:

Vedclass · Accepted Answer

$-1$ and $+3$

Vedclass · Answer

(B) For $CaC_2$: The oxidation state of $Ca$ is $+2$. Let the oxidation state of $C$ be $x$. Thus,$+2 + 2x = 0$,which gives $x = -1$.For $K_2C_2O_4$: The oxidation state of $K$ is $+1$ and $O$ is $-2$. Let the oxidation state of $C$ be $x$. Thus,$2(+1) + 2x + 4(-2) = 0$,which simplifies to $2 + 2x - 8 = 0$,so $2x = 6$ or $x = +3$.Therefore,the oxidation states are $-1$ and $+3$ respectively.

What is the oxidation state of carbon in $CaC_2$ and $K_2C_2O_4$ respectively?

Similar Questions

In the reaction,$MnO_{4(aq)}^{-} + Br_{(aq)}^{-} \rightarrow MnO_{2(s)} + BrO_{3(aq)}^{-}$,the correct change in oxidation number of the species involved is

In which of the following species is the oxidation number of iodine fractional?

What is the oxidation number of carbon in methanal?

The oxidation number of carbon in $H_2C_2O_4$ is:

What is the oxidation number of $Fe$ and $Cr$ in $FeCr_2O_4$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module