(A) $FeCr_2O_4$ is a mixed oxide,which can be represented as $FeO \cdot Cr_2O_3$.In $FeO$,the oxidation state of $Fe$ is $+2$ because oxygen is $-2$.I

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(A) $FeCr_2O_4$ is a mixed oxide,which can be represented as $FeO \cdot Cr_2O_3$.In $FeO$,the oxidation state of $Fe$ is $+2$ because oxygen is $-2$.In $Cr_2O_3$,let the oxidation state of $Cr$ be $x$:$2(x) + 3(-2) = 0$$2x - 6 = 0$$2x = 6$$x = +3$Therefore,the oxidation number of $Fe$ is $+2$ and $Cr$ is $+3$.