Find the unit vector in the direction of 2hat | vedclass

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Question

(A) Let the vector be $\vec{A} = 2\hat{i} + 3\hat{j} + 4\hat{k}$.The magnitude of the vector is given by $|\vec{A}| = \sqrt{2^2 + 3^2 + 4^2}$.$|\vec{A

Vedclass · Accepted Answer

$\frac{2\hat{i} + 3\hat{j} + 4\hat{k}}{\sqrt{29}}$

Vedclass · Answer

(A) Let the vector be $\vec{A} = 2\hat{i} + 3\hat{j} + 4\hat{k}$.The magnitude of the vector is given by $|\vec{A}| = \sqrt{2^2 + 3^2 + 4^2}$.$|\vec{A}| = \sqrt{4 + 9 + 16} = \sqrt{29}$.The unit vector $\hat{A}$ in the direction of $\vec{A}$ is defined as $\hat{A} = \frac{\vec{A}}{|\vec{A}|}$.Therefore,$\hat{A} = \frac{2\hat{i} + 3\hat{j} + 4\hat{k}}{\sqrt{29}}$.

Find the unit vector in the direction of $2\hat{i} + 3\hat{j} + 4\hat{k}$.

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