The gravitational force between two objects i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Newton's law of universal gravitation,the force $F$ between two objects of masses $m_1$ and $m_2$ separated by a distance $r$ is give

Vedclass · Accepted Answer

$0.25$

Vedclass · Answer

(A) According to Newton's law of universal gravitation,the force $F$ between two objects of masses $m_1$ and $m_2$ separated by a distance $r$ is given by $F = G \frac{m_1 m_2}{r^2}$.This implies that $F \propto \frac{1}{r^2}$.Let the initial force be $F_1 = 1 \ N$ at distance $r_1 = r$.When the distance is doubled,$r_2 = 2r$.The new force $F_2$ is given by the ratio: $\frac{F_2}{F_1} = \left(\frac{r_1}{r_2}\right)^2$.Substituting the values: $\frac{F_2}{1} = \left(\frac{r}{2r}\right)^2 = \left(\frac{1}{2}\right)^2 = \frac{1}{4}$.Therefore,$F_2 = \frac{1}{4} \ N = 0.25 \ N$.

The gravitational force between two objects is $1 \ N$. If the distance between the two objects is doubled,what will be the new gravitational force between them (in $N$)?

Similar Questions

Two astronauts are floating in gravitational free space after having lost contact with their spaceship. The two will:

Two spheres of masses $m$ and $M$ are situated in air and the gravitational force between them is $F.$ The space around the masses is now filled with a liquid of specific gravity $3.$ The gravitational force will now be

Two identical particles each of mass $m$ go round a circle of radius $a$ under the action of their mutual gravitational attraction. The angular speed of each particle will be

Find the gravitational force between two stones, each of mass $2 \,kg$ and separated by a distance $1 \,m$ in vacuum.

Six point masses of mass $m$ each are at the vertices of a regular hexagon of side $l$. Calculate the net gravitational force on any one of the masses.

Vedclass Test Series

Exam Paper Generator

Online Exam Module