(A) In an $fcc$ unit cell,there are $8$ corners and $6$ face centers.Number of atoms $A$ at corners = $8 \times \frac{1}{8} = 1$.If one atom $A$ is mi

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(A) In an $fcc$ unit cell,there are $8$ corners and $6$ face centers.Number of atoms $A$ at corners = $8 \times \frac{1}{8} = 1$.If one atom $A$ is missing,the number of atoms $A = 1 - \frac{1}{8} = \frac{7}{8}$.Number of atoms $B$ at face centers = $6 \times \frac{1}{2} = 3$.The ratio of $A:B = \frac{7}{8} : 3 = 7 : 24$.Therefore,the molecular formula is $A_7B_{24}$.

Class 12 Chemistry Solid State Crystal structure and Coordination number

Medium

In an $fcc$ crystal lattice,atoms $A$ are present at the corners and atoms $B$ are present at the face centers. If one atom $A$ is missing from a corner,what is the molecular formula of the compound?

A
$A_7B_{24}$
B
$A_8B_{24}$
C
$A_7B_8$
D
$A_{24}B_7$

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Crystal structure and Coordination number

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In an $fcc$ crystal lattice,atoms $A$ are present at the corners and atoms $B$ are present at the face centers. If one atom $A$ is missing from a corner,what is the molecular formula of the compound?

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