Discuss the $[CoF_6]^{3-}$ complex species based on Valence Bond Theory $(VBT)$.

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(N/A) $1$. The central metal ion is $Co^{3+}$,which has an electronic configuration of $[Ar] 3d^6$.
$2$. In the presence of the weak field ligand $F^-$,the $d$-electrons do not pair up.
$3$. The $Co^{3+}$ ion uses one $4s$,three $4p$,and two $4d$ orbitals to undergo $sp^3d^2$ hybridization.
$4$. Six pairs of electrons from six $F^-$ ions occupy these six $sp^3d^2$ hybrid orbitals.
$5$. Since the outer $4d$ orbitals are used,it is an outer orbital complex (high spin complex).
$6$. Due to the presence of four unpaired electrons in the $3d$ orbitals,the complex is paramagnetic.

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Which one of the following is square planar in structure and has diamagnetic property?

The tetracyanonickelate $(II)$ complex ion has a ..... geometry.

Match List – $I$ with List – $II$:
List - $I$ (Complex)List – $II$ (Geometry)
$(a)$ $[Co(NH_3)_6]^{3+}$$(i)$ Trigonal bipyramidal
$(b)$ $[NiCl_4]^{2-}$(ii) Octahedral
$(c)$ $[Ni(CN)_4]^{2-}$(iii) Tetrahedral
$(d)$ $[Fe(CO)_5]$(iv) Square planar

Choose the correct answer from the options given below.

Match the coordination number and type of hybridisation with the distribution of hybrid orbitals in space based on Valence Bond Theory.
Coordination number and type of hybridisation Distribution of hybrid orbitals in space
$a. 4, sp^3$ $i. \text{trigonal bipyramidal}$
$b. 4, dsp^2$ $ii. \text{octahedral}$
$c. 5, sp^3d$ $iii. \text{tetrahedral}$
$d. 6, d^2sp^3$ $iv. \text{square planar}$

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What is the number of $d$-electrons in the metal ion of the tetrahedral complex $K_2[NiCl_4]$?

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