If the equation y = x^2 r + M^1 L^1 T^{-2} is | vedclass

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(A) According to the principle of homogeneity of dimensions,the dimensions of each term in an equation must be the same.Given the equation $y = x^2 r

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$M^1 L^0 T^{-2}$

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(A) According to the principle of homogeneity of dimensions,the dimensions of each term in an equation must be the same.Given the equation $y = x^2 r + M^1 L^1 T^{-2}$,the dimensions of $x^2 r$ must be equal to the dimensions of $M^1 L^1 T^{-2}$.Let $[x^2]$ be the dimensional formula of $x^2$ and $[r] = L^1$ (as $r$ is displacement).So,$[x^2] \cdot [r] = M^1 L^1 T^{-2}$.$[x^2] \cdot L^1 = M^1 L^1 T^{-2}$.$[x^2] = \frac{M^1 L^1 T^{-2}}{L^1}$.$[x^2] = M^1 L^0 T^{-2}$.

If the equation $y = x^2 r + M^1 L^1 T^{-2}$ is dimensionally correct,find the dimensional formula of $x^2$. (Here,$r$ represents displacement.)

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