Find the dimensional formula of rho g v,where | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The dimensional formula of density $\rho$ is $[M L^{-3}]$.The dimensional formula of acceleration $g$ is $[L T^{-2}]$.The dimensional formula of v

Vedclass · Accepted Answer

$[M L^{-1} T^{-3}]$

Vedclass · Answer

(A) The dimensional formula of density $\rho$ is $[M L^{-3}]$.The dimensional formula of acceleration $g$ is $[L T^{-2}]$.The dimensional formula of velocity $v$ is $[L T^{-1}]$.Now,the dimensional formula of the product $\rho g v$ is given by:$[\rho g v] = [\rho] [g] [v]$$[\rho g v] = [M L^{-3}] [L T^{-2}] [L T^{-1}]$$[\rho g v] = [M L^{-3+1+1} T^{-2-1}]$$[\rho g v] = [M L^{-1} T^{-3}]$

Column-$1$	Column-$2$
$(a)$ Wave vector	$(i)$ $M^1L^0T^{-3}$
$(b)$ Linear mass density	$(ii)$ $M^1L^{-1}T^{-2}$
$(c)$ Intensity of a wave	$(iii)$ $M^0L^{-1}T^0$
$(d)$ Volume elasticity coefficient	$(iv)$ $M^1L^{-1}T^0$

Find the dimensional formula of $\rho g v$,where $\rho = \text{density}$,$g = \text{acceleration}$,and $v = \text{velocity}$.

Similar Questions

The dimensional formula of the universal gas constant is:

Given that $\int {e^{ax}} dx = a^m e^{ax} + C$,then which statement is incorrect (Dimension of $x = L^1$)?

Match Column-$1$ with Column-$2$.
Column-$1$ Column-$2$
$(a)$ Wave vector $(i)$ $M^1L^0T^{-3}$
$(b)$ Linear mass density $(ii)$ $M^1L^{-1}T^{-2}$
$(c)$ Intensity of a wave $(iii)$ $M^0L^{-1}T^0$
$(d)$ Volume elasticity coefficient $(iv)$ $M^1L^{-1}T^0$

The dimensions of surface tension are

The dimensional formula for latent heat is

Vedclass Test Series

Exam Paper Generator

Online Exam Module