(C) Work done $(W)$ is defined by the formula $W = F \cdot d \cdot \cos(\theta)$,where $F$ is the applied force,$d$ is the displacement,and $\theta$ i

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(C) Work done $(W)$ is defined by the formula $W = F \cdot d \cdot \cos(\theta)$,where $F$ is the applied force,$d$ is the displacement,and $\theta$ is the angle between the force and displacement vectors.Since the force $(F)$ and the displacement $(d)$ are the same for both objects,and assuming the force is applied in the direction of displacement $(\theta = 0^\circ)$,the work done is $W = F \cdot d$.Because $F$ and $d$ are identical for both,the work done on both objects is equal,regardless of their masses.

Class 11 Physics Work, Energy, Power and Collision Work Done by Constant Force

Medium

$A$ heavy object and a light object are placed on the same surface. If the same force is applied to both for the same displacement,on which object is more work done by the force?

A
The heavy object
B
The light object
C
Both have the same work done
D
Cannot be determined

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Work, Energy, Power and Collision

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Work Done by Constant Force

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EasyAP EAMCET 2021

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MediumAIPMT 2006

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$A$ heavy object and a light object are placed on the same surface. If the same force is applied to both for the same displacement,on which object is more work done by the force?

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$A$ block of mass $m$ is kept in an elevator which starts moving downward with an acceleration $a$ as shown in the figure. The block is observed by two observers $A$ and $B$ for a time interval $t_0$. According to observer $B$,the net work done on the block is

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