How does the acceleration due to gravity (g) | vedclass

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(B) The acceleration due to gravity on the surface of the Earth is given by the formula $g' = g - \omega^2 R \cos^2 \phi$,where $\phi$ is the latitude

Vedclass · Accepted Answer

It increases as we move from the equator to the poles.

Vedclass · Answer

(B) The acceleration due to gravity on the surface of the Earth is given by the formula $g' = g - \omega^2 R \cos^2 \phi$,where $\phi$ is the latitude.As we move from the equator $(\phi = 0^\circ)$ to the poles $(\phi = 90^\circ)$,the value of $\cos^2 \phi$ decreases.Consequently,the term $\omega^2 R \cos^2 \phi$ decreases,which causes the effective acceleration due to gravity $(g')$ to increase.Therefore,$g$ is minimum at the equator and maximum at the poles.

How does the acceleration due to gravity $(g)$ at a location on Earth change with latitude?

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