If the kinetic energy of a satellite is $6 \times 10^9 \ J$,what will be its potential energy and total energy?

  • A
    Potential energy = $-12 \times 10^9 \ J$,Total energy = $-6 \times 10^9 \ J$
  • B
    Potential energy = $12 \times 10^9 \ J$,Total energy = $6 \times 10^9 \ J$
  • C
    Potential energy = $-6 \times 10^9 \ J$,Total energy = $-12 \times 10^9 \ J$
  • D
    Potential energy = $6 \times 10^9 \ J$,Total energy = $-6 \times 10^9 \ J$

Explore More

Similar Questions

$A$ launching vehicle carrying an artificial satellite of mass $m$ is set for launch on the surface of the earth of mass $M$ and radius $R$. If the satellite is intended to move in a circular orbit of radius $7R$,the minimum energy required to be spent by the launching vehicle on the satellite is ($G$ is the gravitational constant).

$A$ satellite of mass $m$ is placed at a distance $r$ from the centre of the Earth (mass $M$). The mechanical energy of the satellite is

$A$ satellite is revolving around the Earth with orbital speed $v_0$. If it stops suddenly,the speed with which it will strike the surface of the Earth would be: ($v_e =$ escape velocity of a particle on the Earth's surface)

Difficult
View Solution

If the time period of revolution of a satellite is $T$,then its kinetic energy is proportional to

$A$ satellite of mass $m$,revolving around the Earth of radius $r$,has kinetic energy $E$. Its angular momentum is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo